## Thursday, November 7, 2013

### E Exercises

Andromaque Jean-Louis problem 9.54 Faced with rising fax costs, a unanimous issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail instead. Exceptions are allowed, but they tidy sum the average to be 10 or below. The firm examined 35 randomly chosen fax transmissions during the next year, yielding a sample tight of 14.44 with a standard deviation of 4.45 pages. (a) At the .01 level of significance, is the true entertain great than 10? (b) manipulation Excel to bugger off the right-tail p-value. a) At the .01 level of significance, is the true mean great than 10? The critical value for one-tail essay with of import is equal to 1 % which df=34 which is equal to 2.32634 The test statistic is z(14.44) which translates to (14.44-10)/[4.45/? (35)] equals 5.9028 Ha: ? > 10 Ho: ? = 10 The test statistics is in the spurned interval of Ho. thither is enough evidence supporting the conduct the true mean is greater than 10. b) Use Excel to find the right-tail p-value? p-value = P(5.9028 < t < 10) = 0.00000057579... = 1 NORMSDIST(5.9027) Problem 9.56 A take was flipped 60 times and came up heads 38 times. (a) At the . 10 level of significance, is the coin aslant toward heads? Show your finale rule and calculations. (b) channelize a p-value and interpret it. a) At the .10 level of significance, is the coin dyed toward heads? Show your decision rule and calculations. Ha: p> 0.5 Ho: p< 0.5 ? = np = (60)(0.5) = 30 ? = ?npq = ?(0.5)(0.5)(60) = 3.8730 (38 - 30) / 3.8730 = 2.0656 As the test statistic is greater than critical value, Re! ject Ho The test reflects that the coin is biased toward heads. b) Calculate a p-value and interpret it. p(z > 2.0656) = 0.0194 The Null possibleness is rejected and the claim is supported.If you want to get a wide essay, devote it on our website: OrderCustomPaper.com

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